From 482ccd2f7497a79ca83e998f54e823e7cedaaa6e Mon Sep 17 00:00:00 2001 From: Szabolcs Nagy Date: Tue, 11 Dec 2012 23:06:20 +0100 Subject: math: rewrite inverse hyperbolic functions to be simpler/smaller modifications: * avoid unsigned->signed integer conversion * do not handle special cases when they work correctly anyway * more strict threshold values (0x1p26 instead of 0x1p28 etc) * smaller code, cleaner branching logic * same precision as the old code: acosh(x) has up to 2ulp error in [1,1.125] asinh(x) has up to 1.6ulp error in [0.125,0.5], [-0.5,-0.125] atanh(x) has up to 1.7ulp error in [0.125,0.5], [-0.5,-0.125] --- src/math/atanhl.c | 69 +++++++++++++++---------------------------------------- 1 file changed, 18 insertions(+), 51 deletions(-) (limited to 'src/math/atanhl.c') diff --git a/src/math/atanhl.c b/src/math/atanhl.c index 931bae32..b4c5e58b 100644 --- a/src/math/atanhl.c +++ b/src/math/atanhl.c @@ -1,31 +1,3 @@ -/* origin: OpenBSD /usr/src/lib/libm/src/ld80/e_atanh.c */ -/* - * ==================================================== - * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved. - * - * Developed at SunPro, a Sun Microsystems, Inc. business. - * Permission to use, copy, modify, and distribute this - * software is freely granted, provided that this notice - * is preserved. - * ==================================================== - */ -/* atanhl(x) - * Method : - * 1.Reduced x to positive by atanh(-x) = -atanh(x) - * 2.For x>=0.5 - * 1 2x x - * atanhl(x) = --- * log(1 + -------) = 0.5 * log1p(2 * --------) - * 2 1 - x 1 - x - * - * For x<0.5 - * atanhl(x) = 0.5*log1pl(2x+2x*x/(1-x)) - * - * Special cases: - * atanhl(x) is NaN if |x| > 1 with signal; - * atanhl(NaN) is that NaN with no signal; - * atanhl(+-1) is +-INF with signal. - */ - #include "libm.h" #if LDBL_MANT_DIG == 53 && LDBL_MAX_EXP == 1024 @@ -34,31 +6,26 @@ long double atanhl(long double x) return atanh(x); } #elif LDBL_MANT_DIG == 64 && LDBL_MAX_EXP == 16384 -static const long double huge = 1e4900L; - +/* atanh(x) = log((1+x)/(1-x))/2 = log1p(2x/(1-x))/2 ~= x + x^3/3 + o(x^5) */ long double atanhl(long double x) { - long double t; - int32_t ix; - uint32_t se,i0,i1; + union { + long double f; + struct{uint64_t m; uint16_t se; uint16_t pad;} i; + } u = {.f = x}; + unsigned e = u.i.se & 0x7fff; + unsigned s = u.i.se >> 15; + + /* |x| */ + u.i.se = e; + x = u.f; - GET_LDOUBLE_WORDS(se, i0, i1, x); - ix = se & 0x7fff; - if ((ix+((((i0&0x7fffffff)|i1)|(-((i0&0x7fffffff)|i1)))>>31)) > 0x3fff) - /* |x| > 1 */ - return (x-x)/(x-x); - if (ix == 0x3fff) - return x/0.0; - if (ix < 0x3fe3 && huge+x > 0.0) /* x < 2**-28 */ - return x; - SET_LDOUBLE_EXP(x, ix); - if (ix < 0x3ffe) { /* x < 0.5 */ - t = x + x; - t = 0.5*log1pl(t + t*x/(1.0 - x)); - } else - t = 0.5*log1pl((x + x)/(1.0 - x)); - if (se <= 0x7fff) - return t; - return -t; + if (e < 0x3fff - 1) { + /* |x| < 0.5, up to 1.7ulp error */ + x = 0.5*log1pl(2*x + 2*x*x/(1-x)); + } else { + x = 0.5*log1pl(2*x/(1-x)); + } + return s ? -x : x; } #endif -- cgit v1.2.1