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+/* origin: FreeBSD /usr/src/lib/msun/src/e_sqrt.c */
+/*
+ * ====================================================
+ * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
+ *
+ * Developed at SunSoft, a Sun Microsystems, Inc. business.
+ * Permission to use, copy, modify, and distribute this
+ * software is freely granted, provided that this notice
+ * is preserved.
+ * ====================================================
+ */
+/* sqrt(x)
+ * Return correctly rounded sqrt.
+ * ------------------------------------------
+ * | Use the hardware sqrt if you have one |
+ * ------------------------------------------
+ * Method:
+ * Bit by bit method using integer arithmetic. (Slow, but portable)
+ * 1. Normalization
+ * Scale x to y in [1,4) with even powers of 2:
+ * find an integer k such that 1 <= (y=x*2^(2k)) < 4, then
+ * sqrt(x) = 2^k * sqrt(y)
+ * 2. Bit by bit computation
+ * Let q = sqrt(y) truncated to i bit after binary point (q = 1),
+ * i 0
+ * i+1 2
+ * s = 2*q , and y = 2 * ( y - q ). (1)
+ * i i i i
+ *
+ * To compute q from q , one checks whether
+ * i+1 i
+ *
+ * -(i+1) 2
+ * (q + 2 ) <= y. (2)
+ * i
+ * -(i+1)
+ * If (2) is false, then q = q ; otherwise q = q + 2 .
+ * i+1 i i+1 i
+ *
+ * With some algebric manipulation, it is not difficult to see
+ * that (2) is equivalent to
+ * -(i+1)
+ * s + 2 <= y (3)
+ * i i
+ *
+ * The advantage of (3) is that s and y can be computed by
+ * i i
+ * the following recurrence formula:
+ * if (3) is false
+ *
+ * s = s , y = y ; (4)
+ * i+1 i i+1 i
+ *
+ * otherwise,
+ * -i -(i+1)
+ * s = s + 2 , y = y - s - 2 (5)
+ * i+1 i i+1 i i
+ *
+ * One may easily use induction to prove (4) and (5).
+ * Note. Since the left hand side of (3) contain only i+2 bits,
+ * it does not necessary to do a full (53-bit) comparison
+ * in (3).
+ * 3. Final rounding
+ * After generating the 53 bits result, we compute one more bit.
+ * Together with the remainder, we can decide whether the
+ * result is exact, bigger than 1/2ulp, or less than 1/2ulp
+ * (it will never equal to 1/2ulp).
+ * The rounding mode can be detected by checking whether
+ * huge + tiny is equal to huge, and whether huge - tiny is
+ * equal to huge for some floating point number "huge" and "tiny".
+ *
+ * Special cases:
+ * sqrt(+-0) = +-0 ... exact
+ * sqrt(inf) = inf
+ * sqrt(-ve) = NaN ... with invalid signal
+ * sqrt(NaN) = NaN ... with invalid signal for signaling NaN
+ */
+
+#include "libm.h"
+
+static const double one = 1.0, tiny = 1.0e-300;
+
+double sqrt(double x)
+{
+ double z;
+ int32_t sign = (int)0x80000000;
+ int32_t ix0,s0,q,m,t,i;
+ uint32_t r,t1,s1,ix1,q1;
+
+ EXTRACT_WORDS(ix0, ix1, x);
+
+ /* take care of Inf and NaN */
+ if ((ix0&0x7ff00000) == 0x7ff00000) {
+ return x*x + x; /* sqrt(NaN)=NaN, sqrt(+inf)=+inf, sqrt(-inf)=sNaN */
+ }
+ /* take care of zero */
+ if (ix0 <= 0) {
+ if (((ix0&~sign)|ix1) == 0)
+ return x; /* sqrt(+-0) = +-0 */
+ if (ix0 < 0)
+ return (x-x)/(x-x); /* sqrt(-ve) = sNaN */
+ }
+ /* normalize x */
+ m = ix0>>20;
+ if (m == 0) { /* subnormal x */
+ while (ix0 == 0) {
+ m -= 21;
+ ix0 |= (ix1>>11);
+ ix1 <<= 21;
+ }
+ for (i=0; (ix0&0x00100000) == 0; i++)
+ ix0<<=1;
+ m -= i - 1;
+ ix0 |= ix1>>(32-i);
+ ix1 <<= i;
+ }
+ m -= 1023; /* unbias exponent */
+ ix0 = (ix0&0x000fffff)|0x00100000;
+ if (m & 1) { /* odd m, double x to make it even */
+ ix0 += ix0 + ((ix1&sign)>>31);
+ ix1 += ix1;
+ }
+ m >>= 1; /* m = [m/2] */
+
+ /* generate sqrt(x) bit by bit */
+ ix0 += ix0 + ((ix1&sign)>>31);
+ ix1 += ix1;
+ q = q1 = s0 = s1 = 0; /* [q,q1] = sqrt(x) */
+ r = 0x00200000; /* r = moving bit from right to left */
+
+ while (r != 0) {
+ t = s0 + r;
+ if (t <= ix0) {
+ s0 = t + r;
+ ix0 -= t;
+ q += r;
+ }
+ ix0 += ix0 + ((ix1&sign)>>31);
+ ix1 += ix1;
+ r >>= 1;
+ }
+
+ r = sign;
+ while (r != 0) {
+ t1 = s1 + r;
+ t = s0;
+ if (t < ix0 || (t == ix0 && t1 <= ix1)) {
+ s1 = t1 + r;
+ if ((t1&sign) == sign && (s1&sign) == 0)
+ s0++;
+ ix0 -= t;
+ if (ix1 < t1)
+ ix0--;
+ ix1 -= t1;
+ q1 += r;
+ }
+ ix0 += ix0 + ((ix1&sign)>>31);
+ ix1 += ix1;
+ r >>= 1;
+ }
+
+ /* use floating add to find out rounding direction */
+ if ((ix0|ix1) != 0) {
+ z = one - tiny; /* raise inexact flag */
+ if (z >= one) {
+ z = one + tiny;
+ if (q1 == (uint32_t)0xffffffff) {
+ q1 = 0;
+ q++;
+ } else if (z > one) {
+ if (q1 == (uint32_t)0xfffffffe)
+ q++;
+ q1 += 2;
+ } else
+ q1 += q1 & 1;
+ }
+ }
+ ix0 = (q>>1) + 0x3fe00000;
+ ix1 = q1>>1;
+ if (q&1)
+ ix1 |= sign;
+ ix0 += m << 20;
+ INSERT_WORDS(z, ix0, ix1);
+ return z;
+}